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/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */class Solution { public TreeNode sortedArrayToBST(int[] nums) { return help(nums, 0, nums.length - 1); } public TreeNode help(int[] arr, int left, int right) { //采用二分法 取中间的一个元素作为根节点 这样可以保证高度差不超过一 if(left > right) { return null; } int mid = left + (right - left) / 2; TreeNode root = new TreeNode(arr[mid]); root.left = help(arr, left, mid - 1); root.right = help(arr, mid + 1, right); return root; }}
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